Suppose 2.47g of sodium phosphate Na3PO4 are dissolved in 130.mL of water. Find the composition of the resulting electrolyte solution.In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row.Then, calculate the concentration of each ion in mEqL, and write the concentration in the second column of each row. Be sure you round your answers to the correct number of significant digits.
Question
Suppose 2.47g of sodium phosphate Na3PO4 are dissolved in 130.mL of water. Find the composition of the resulting electrolyte solution.In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row.Then, calculate the concentration of each ion in mEqL, and write the concentration in the second column of each row. Be sure you round your answers to the correct number of significant digits.
Solution
First, let's identify the ions that will be present in the solution. Sodium phosphate (Na3PO4) is a salt that will dissociate completely in water to form its constituent ions. These are:
- Sodium ion (Na+)
- Phosphate ion (PO4^3-)
Now, let's calculate the concentration of each ion in mEq/L.
-
Sodium ion (Na+):
Sodium phosphate has three sodium ions. Therefore, the amount of sodium ions is 2.47 g * (3 mol Na/164 g Na3PO4) = 0.045 mol Na.
The volume of the solution is 130 mL, or 0.130 L.
Therefore, the concentration of sodium ions is 0.045 mol/0.130 L = 0.346 mol/L.
To convert this to mEq/L, we multiply by the charge of the sodium ion (which is +1) and by 1000 (since 1 Eq = 1 mol of charge, and 1 mEq = 0.001 Eq).
Therefore, the concentration of sodium ions is 0.346 mol/L * 1 * 1000 = 346 mEq/L.
-
Phosphate ion (PO4^3-):
Sodium phosphate has one phosphate ion. Therefore, the amount of phosphate ions is 2.47 g * (1 mol PO4/164 g Na3PO4) = 0.015 mol PO4.
Therefore, the concentration of phosphate ions is 0.015 mol/0.130 L = 0.115 mol/L.
To convert this to mEq/L, we multiply by the charge of the phosphate ion (which is -3) and by 1000.
Therefore, the concentration of phosphate ions is 0.115 mol/L * 3 * 1000 = 346 mEq/L.
So, the composition of the resulting electrolyte solution is:
| Ion | Concentration (mEq/L) |
|---|---|
| Na+ | 346 |
| PO4^3- | 346 |
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