First, let's identify the ions that will be present in the solution. When iron(III) chloride, or FeCl3, dissolves in water, it dissociates into its constituent ions: Fe3+ and Cl-.

Now, let's calculate the concentration of each ion in mEq/L.

1. Calculate the number of moles of FeCl3:
The molar mass of FeCl3 is approximately 162.2 g/mol. So, the number of moles of FeCl3 is given by:
Moles = mass / molar mass = 18.9 g / 162.2 g/mol = 0.1165 mol

2. Calculate the volume of the solution in liters:
Volume = 830 mL = 0.830 L

3. Calculate the concentration of Fe3+:
Since each molecule of FeCl3 produces one Fe3+ ion, the concentration of Fe3+ is the same as the concentration of FeCl3.
Concentration = moles / volume = 0.1165 mol / 0.830 L = 0.1404 mol/L

To convert this to mEq/L, we multiply by the charge of the ion (3) and by 1000 (since 1 Eq = 1 mol of charge, and 1 mEq = 1/1000 Eq):
Concentration = 0.1404 mol/L * 3 * 1000 = 421.2 mEq/L

4. Calculate the concentration of Cl-:
Each molecule of FeCl3 produces three Cl- ions, so the concentration of Cl- is three times the concentration of FeCl3.
Concentration = 3 * 0.1165 mol / 0.830 L = 0.4212 mol/L

To convert this to mEq/L, we multiply by the charge of the ion (1) and by 1000:
Concentration = 0.4212 mol/L * 1 * 1000 = 421.2 mEq/L

So, the composition of the solution is as follows:

| Ion | Concentration (mEq/L) |
|-----|-----------------------|
| Fe3+| 421.2 |
| Cl- | 1263.6 |

Question

First, let's identify the ions that will be present in the solution. When iron(III) chloride, or FeCl3, dissolves in water, it dissociates into its constituent ions: Fe3+ and Cl-.

Now, let's calculate the concentration of each ion in mEq/L.

1. Calculate the number of moles of FeCl3:
   The molar mass of FeCl3 is approximately 162.2 g/mol. So, the number of moles of FeCl3 is given by:
   Moles = mass / molar mass = 18.9 g / 162.2 g/mol = 0.1165 mol

2. Calculate the volume of the solution in liters:
   Volume = 830 mL = 0.830 L

3. Calculate the concentration of Fe3+:
   Since each molecule of FeCl3 produces one Fe3+ ion, the concentration of Fe3+ is the same as the concentration of FeCl3. 
   Concentration = moles / volume = 0.1165 mol / 0.830 L = 0.1404 mol/L

To convert this to mEq/L, we multiply by the charge of the ion (3) and by 1000 (since 1 Eq = 1 mol of charge, and 1 mEq = 1/1000 Eq):
   Concentration = 0.1404 mol/L * 3 * 1000 = 421.2 mEq/L

4. Calculate the concentration of Cl-:
   Each molecule of FeCl3 produces three Cl- ions, so the concentration of Cl- is three times the concentration of FeCl3. 
   Concentration = 3 * 0.1165 mol / 0.830 L = 0.4212 mol/L

To convert this to mEq/L, we multiply by the charge of the ion (1) and by 1000:
   Concentration = 0.4212 mol/L * 1 * 1000 = 421.2 mEq/L

So, the composition of the solution is as follows:

| Ion | Concentration (mEq/L) |
|-----|-----------------------|
| Fe3+| 421.2                 |
| Cl- | 1263.6                |

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