A block weighs 1000kg and is let at a speed of 120kmph for a distance of 50 meters. What is the acceleration experienced by the block and work done by the block?Write the calculations along with the answer
Question
A block weighs 1000kg and is let at a speed of 120kmph for a distance of 50 meters. What is the acceleration experienced by the block and work done by the block?Write the calculations along with the answer
Solution
First, we need to convert the speed from km/h to m/s because the standard unit of speed in physics is m/s.
1 km = 1000 m 1 hour = 3600 s
So, 120 km/h = 120 * 1000 m / 3600 s = 33.33 m/s
Next, we use the formula for acceleration, which is final velocity squared minus initial velocity squared divided by 2 times the distance. In this case, the block comes to rest, so the final velocity is 0.
Acceleration (a) = (v_f^2 - v_i^2) / (2 * d) a = (0 - (33.33)^2) / (2 * 50) a = -11.11 m/s^2
The negative sign indicates that the block is decelerating.
Now, to find the work done, we use the formula for work, which is force times distance. Force is mass times acceleration.
Force (F) = m * a F = 1000 kg * 11.11 m/s^2 F = 11110 N
Work (W) = F * d W = 11110 N * 50 m W = 555500 J
So, the block experiences an acceleration of 11.11 m/s^2 and the work done by the block is 555500 J.
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