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A die is tossed twice. The probability of having a number greater than 4 on each toss is ans. none 2/3 1/9 1/3

Question

A die is tossed twice. The probability of having a number greater than 4 on each toss is ans. none

2/3

1/9

1/3

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Solution

The probability of rolling a number greater than 4 (i.e., 5 or 6) on a single die is 2 out of 6, or 1/3, because a die has six faces.

When the die is tossed twice, the events are independent, meaning the outcome of the first toss does not affect the outcome of the second toss.

Therefore, the probability of both events happening is the product of their individual probabilities.

So, the probability of rolling a number greater than 4 on both tosses is (1/3) * (1/3) = 1/9.

This problem has been solved

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