4 men throw a die each simultaneously. Find the probability that at least 2 people get the same number.

Step 1: Identify the total number of outcomes

Each man can throw any of the 6 faces of the die. Since there are 4 men, the total number of outcomes is 6^4 = 1296.

Step 2: Identify the number of outcomes where no two people get the same number

The first man can throw any of the 6 faces of the die. The second man can throw any of the remaining 5 faces. The third man can throw any of the remaining 4 faces. The fourth man can throw any of the remaining 3 faces. So, the number of outcomes where no two people get the same number is 654*3 = 360.

Step 3: Identify the number of outcomes where at least two people get the same number

This is the complement of the event where no two people get the same number. So, the number of outcomes where at least two people get the same number is the total number of outcomes minus the number of outcomes where no two people get the same number. That is, 1296 - 360 = 936.

Step 4: Calculate the probability

The probability of an event is the number of outcomes where the event occurs divided by the total number of outcomes. So, the probability that at least two people get the same number is 936/1296 = 0.72 (approximately).