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Consider only the discriminant, b2 - 4ac, to determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist.-9 - 5x2 = 4x - 12Group of answer choicesOne real solutionTwo different imaginary-number solutionsTwo different real-number solutionsNext

Question

Consider only the discriminant, b2 - 4ac, to determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist.-9 - 5x2 = 4x - 12Group of answer choicesOne real solutionTwo different imaginary-number solutionsTwo different real-number solutionsNext

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Solution

The given equation is -9 - 5x^2 = 4x - 12.

First, we need to rewrite this equation in the standard quadratic form ax^2 + bx + c = 0.

Rearranging the terms, we get 5x^2 + 4x + 3 = 0.

Here, a = 5, b = 4, and c = 3.

The discriminant of a quadratic equation is given by b^2 - 4ac.

Substituting the values of a, b, and c, we get:

Discriminant = 4^2 - 453 = 16 - 60 = -44.

Since the discriminant is less than 0, the quadratic equation will have two different imaginary-number solutions.

This problem has been solved

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