Consider the following equation:−3𝑥2−2𝑥−5=0First calculate the discriminant.Δ= How many real solutions does this equation have? Two real solutions One repeated solution No real solutions
Question
Consider the following equation:−3𝑥2−2𝑥−5=0First calculate the discriminant.Δ= How many real solutions does this equation have? Two real solutions One repeated solution No real solutions
Solution
The equation given is a quadratic equation of the form ax^2 + bx + c = 0. The discriminant of a quadratic equation is given by the formula Δ = b^2 - 4ac.
In this case, a = -3, b = -2, and c = -5.
Substituting these values into the formula, we get:
Δ = (-2)^2 - 4*(-3)*(-5) Δ = 4 - 60 Δ = -56
Since the discriminant is less than zero, this means that the equation has no real solutions.
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