Consider the hydrolysis of t-butyliodide,(CH3)3I + H2O → (CH3)3COH + HIThe equation governing the rate of this reaction israte = k[(CH3)3I].What is the order of reaction with regard to H2O?Group of answer choices0th order1/2 order2nd order1st order
Question
Consider the hydrolysis of t-butyliodide,(CH3)3I + H2O → (CH3)3COH + HIThe equation governing the rate of this reaction israte = k[(CH3)3I].What is the order of reaction with regard to H2O?Group of answer choices0th order1/2 order2nd order1st order
Solution
The order of reaction with regard to H2O is 0th order. This is because the rate of the reaction does not depend on the concentration of H2O, as it is not included in the rate equation.
Similar Questions
Consider the hydrolysis of t-butyliodide,(CH3)3I + H2O → (CH3)3COH + HIThe equation governing the rate of this reaction israte = k[(CH3)3I]What will happen to the initial rate if the concentration of (CH3)3I is doubled?Group of answer choicesit will be quadrupledit will be doubledit will remain unchanged
For the following reaction…BrO3– + 5Br– + 6H+ → 3 Br2 + 3H2OThe rate law is…Rate = k[BrO3–][Br–][H+]2What is the order of reaction with respect to H+?Group of answer choices3rd order0th order2nd order1st order
If the rates of reaction are R1 and R2 at concentrations C1 and C2 of a reactant respectively, the order of reaction n (assuming that the concentrations of all other reactants and T remains constant) with respect to that of reactant is given by
Consider the following statements,The rate law for the acid catalysed hydrolysis of an ester being given asRate=k[H+][ester]=k′[ester].If the acid concentration is doubled at constant ester concentration1. The second order rate constant, k is doubled.2. The pseudo first order rate constant, k is double.3. The rate of the reaction is doubled.Which of the above statements are correct?1 and 22 and 31 and 31,2 and 3
Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.