Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2
Question
Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2
Solution
The overall order of a reaction is determined by adding up the exponents in the rate law expression.
In the given rate law expression: Rate = k[NO]^(3/2)[O]^(1/2)
The order with respect to [NO] is 3/2 and the order with respect to [O] is 1/2.
To find the overall order of the reaction, add these two values together:
Overall order = (3/2) + (1/2) = 2
So, the overall order of the reaction is 2.
Similar Questions
Determine the rate of a reaction that follows the rate law:rate = k[A]m[B]n, where:k = 0.2[A] = 3 M[B] = 3 Mm = 1n = 2A.27 (mol/L)/sB.1.2 (mol/L)/sC.5.4 (mol/L)/sD.1.8 (mol/L)/sSUBMITarrow_backPREVIOUS
Write the rate law for the following elementary reaction:2NO(g) + O2(g) → 2NO2(g)Use k1 to stand for the rate constant.
For a reaction A + B → P, the rate law is given by, r = k [A]1/2 [B]2, What is the order of thisreaction?
The rate of the reaction is measured to be 32.0 M / s when [N2] = 0.11 M and [O3] = 0.51 M. Calculate the value of the rate constant. Round your answer to 2 significant digits. =k⋅M−3s−1
Write the rate law for the following elementary reaction:O 3 (g) + NO(g) → O 2 (g) + NO 2 (g)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.