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Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2

Question

Calculate the overall order of the reaction whose rate law expression was predicted as :Rate =k[NO]3/2 [O ]1/2

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Solution

The overall order of a reaction is determined by adding up the exponents in the rate law expression.

In the given rate law expression: Rate = k[NO]^(3/2)[O]^(1/2)

The order with respect to [NO] is 3/2 and the order with respect to [O] is 1/2.

To find the overall order of the reaction, add these two values together:

Overall order = (3/2) + (1/2) = 2

So, the overall order of the reaction is 2.

This problem has been solved

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