What is the output for the following code? 123456789#include <stdio.h>#include <math.h> int main() { double a = 3.0, b = 4.0; double c = sqrt(pow(a, 2) + pow(b, 2)); printf("%.2f", c); return 0;}
Question
What is the output for the following code? 123456789#include <stdio.h>#include <math.h> int main() { double a = 3.0, b = 4.0; double c = sqrt(pow(a, 2) + pow(b, 2)); printf("%.2f", c); return 0;}
Solution
The output of the code will be 5.00.
Here's the step by step explanation:
-
The code first declares two double variables,
aandb, and assigns them the values 3.0 and 4.0 respectively. -
It then calculates the square of
aandbusing thepowfunction, adds them together, and takes the square root of the result using thesqrtfunction. This is essentially calculating the hypotenuse of a right triangle using the Pythagorean theorem (c = sqrt(a^2 + b^2)). -
The result of this calculation (which is 5.0) is then stored in the double variable
c. -
Finally, the
printffunction is used to print the value ofcto the console. The "%.2f" format specifier is used to print the value ofcwith two digits after the decimal point, so the output will be 5.00.
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