To deduce the correct order for the elements in decreasing atomic radius, we need to consider the periodic trends. Atomic radius generally decreases across a period from left to right and increases down a group.

First, let's compare potassium (K) and chlorine (Cl). Potassium is located in Group 1 (alkali metals) and chlorine is in Group 17 (halogens). Since potassium is located lower in the periodic table, it will have a larger atomic radius than chlorine. Therefore, we can conclude that K Cl.

Next, let's compare chlorine (Cl) and sulfur (S). Both elements are in the same period (Period 3), but chlorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that Cl S.

Finally, let's compare sulfur (S) and fluorine (F). Both elements are in the same period (Period 3), but fluorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that F S.

Putting it all together, the correct order for the elements in decreasing atomic radius is: F Cl S K.

Question

To deduce the correct order for the elements in decreasing atomic radius, we need to consider the periodic trends. Atomic radius generally decreases across a period from left to right and increases down a group.

First, let's compare potassium (K) and chlorine (Cl). Potassium is located in Group 1 (alkali metals) and chlorine is in Group 17 (halogens). Since potassium is located lower in the periodic table, it will have a larger atomic radius than chlorine. Therefore, we can conclude that K > Cl.

Next, let's compare chlorine (Cl) and sulfur (S). Both elements are in the same period (Period 3), but chlorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that Cl > S.

Finally, let's compare sulfur (S) and fluorine (F). Both elements are in the same period (Period 3), but fluorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that F > S.

Putting it all together, the correct order for the elements in decreasing atomic radius is: F > Cl > S > K.

Knowee AI · Accepted Answer

To deduce the correct order for the elements in decreasing atomic radius, we need to consider the periodic trends. Atomic radius generally decreases across a period from left to right and increases down a group.

First, let's compare potassium (K) and chlorine (Cl). Potassium is located in Group 1 (alkali metals) and chlorine is in Group 17 (halogens). Since potassium is located lower in the periodic table, it will have a larger atomic radius than chlorine. Therefore, we can conclude that K > Cl.

Next, let's compare chlorine (Cl) and sulfur (S). Both elements are in the same period (Period 3), but chlorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that Cl > S.

Finally, let's compare sulfur (S) and fluorine (F). Both elements are in the same period (Period 3), but fluorine is located to the left of sulfur. As we move from left to right across a period, the atomic radius generally decreases. Therefore, we can conclude that F > S.

Putting it all together, the correct order for the elements in decreasing atomic radius is: F > Cl > S > K.

Deduce the correct order for the following elements in order of decreasing atomic radius: S, K, Cl and F.F > Cl > S > KK > F > Cl > SK > S > Cl > FF > Cl > K > S

Question

Solution

Similar Questions

Upgrade your grade with Knowee