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If ๐‘ฅ = 7 โˆ’ 4โˆš3, then the value of โˆš๐‘ฅ + 1โˆš๐‘ฅ :(ii) Prove that :(๐‘ฅ๐‘ž+1๐‘ฅ๐‘+1)๐‘ž+๐‘. (๐‘ฅ๐‘Ÿ+1๐‘ฅ๐‘ž+1)๐‘Ÿ+๐‘ž. (๐‘ฅ๐‘+1๐‘ฅ๐‘Ÿ+1 )๐‘+๐‘Ÿ= 1

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If ๐‘ฅ = 7 โˆ’ 4โˆš3, then the value of โˆš๐‘ฅ + 1โˆš๐‘ฅ :(ii) Prove that :(๐‘ฅ๐‘ž+1๐‘ฅ๐‘+1)๐‘ž+๐‘. (๐‘ฅ๐‘Ÿ+1๐‘ฅ๐‘ž+1)๐‘Ÿ+๐‘ž. (๐‘ฅ๐‘+1๐‘ฅ๐‘Ÿ+1 )๐‘+๐‘Ÿ= 1

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If ๐‘ฅ = 7 โˆ’ 4โˆš3, then the value of โˆš๐‘ฅ + 1โˆš๐‘ฅ :(ii) Prove that :(๐‘ฅ๐‘ž+1๐‘ฅ๐‘+1)๐‘ž+๐‘. (๐‘ฅ๐‘Ÿ+1๐‘ฅ๐‘ž+1)๐‘Ÿ+๐‘ž. (๐‘ฅ๐‘+1๐‘ฅ๐‘Ÿ+1 )๐‘+๐‘Ÿ= 1

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If x = 7 + 4โˆš3 and xy = 1, then the value of (1/x2 + 1/y2) is:7 + 4โˆš3/ 7 - 4โˆš385โˆš319457

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