What is wrong with the following code?int n = 5;int array[5];int i = 3;array[n] = i;It is impossible to declare the variable array this wayThe array array is not entirely initializedWhile it is possible to access array[n], we are not supposed to as this is not the array anymoreNothing is wrongI don't knowSubmit

What is wrong with the following code?int n = 5;int array[5];int i = 3;array[n] = i;

Analyze the following code and choose the correct answer.int[] arr = new int[5];arr = new int[6];The code has compile errors because the variable arr cannot be changed once it is assigned. The code has runtime errors because the variable arr cannot be changed once it is assigned.The code can compile and run fine. The second line assigns a new array to arr.The code has compile errors because we cannot assign a different size array to arr.

Which of the following is not a correct way to initialize an array?a.int n[ 5 ] = { 0, 7, 0, 3, 8, 2 };b.int n[] = { 0, 7, 0, 3, 8, 2 };c.int n[ 5 ] = { 7 };d.int n[ 5 ] = { 9, 1, 9 };

Given the array declaration int arr[5] = {1, 2, 3};, what are the values of arr[3] and arr[4]?Both arr[3] and arr[4] are 0Both arr[3] and arr[4] are uninitializedarr[3] is 3 and arr[4] is 3arr[3] is 2 and arr[4] is 2

Analyze the following code.public class Test {   public static void main(String[] args) {     int[] x = new int[3];     System.out.println("x[0] is " + x[0]);   } } Group of answer choicesThe program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined