A body of mass 'm' kg is lifted by a man to height 'h' in 30 sec another man lifts same body to same height in 60 sec, then find out ratio of their work done :-1 : 22 : 11 : 11 : 4
Question
A body of mass 'm' kg is lifted by a man to height 'h' in 30 sec another man lifts same body to same height in 60 sec, then find out ratio of their work done :-1 : 22 : 11 : 11 : 4
Solution
The work done by each man is given by the formula for work, which is force times distance. In this case, the force is the weight of the body (mass times gravity) and the distance is the height 'h'.
For the first man, the work done is mgh, where g is the acceleration due to gravity.
For the second man, the work done is also mgh, because he is lifting the same body to the same height.
Therefore, the ratio of their work done is 1:1, because they are doing the same amount of work. The time taken to do the work does not affect the amount of work done, so the fact that one man takes longer than the other does not change the ratio.
So, the answer is 1:1.
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