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Solve the simultaneous equations3a−b= −19,3a+4b= −14.

Question

Solve the simultaneous equations3a−b= −19,3a+4b= −14.

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Solution

Sure, let's solve these simultaneous equations step by step.

Step 1: Write down the equations:

3a - b = -19 ---- (Equation 1)

3a + 4b = -14 ---- (Equation 2)

Step 2: To eliminate one of the variables, we can subtract Equation 2 from Equation 1:

(3a - b) - (3a + 4b) = -19 - (-14)

This simplifies to:

-5b = -5

Step 3: Solve for b by dividing both sides by -5:

b = -5 / -5 = 1

Step 4: Substitute b = 1 into Equation 1:

3a - 1 = -19

Step 5: Solve for a:

3a = -19 + 1

3a = -18

a = -18 / 3

a = -6

So, the solution to the simultaneous equations is a = -6 and b = 1.

This problem has been solved

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