Solve the simultaneous equations3a−2b= 5,8a−3b= 11.
Question
Solve the simultaneous equations3a−2b= 5,8a−3b= 11.
Solution
Sure, here are the steps to solve the simultaneous equations:
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We have the two equations: 3a - 2b = 5 ...(1) 8a - 3b = 11 ...(2)
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To eliminate one of the variables, we can multiply the first equation by 3 and the second equation by 2. This gives us: 9a - 6b = 15 ...(3) 16a - 6b = 22 ...(4)
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Subtract equation (4) from equation (3) to eliminate b: -7a = -7 This simplifies to a = 1.
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Substitute a = 1 into the first equation (1): 3(1) - 2b = 5 3 - 2b = 5 -2b = 5 - 3 -2b = 2 Divide by -2 to solve for b, we get b = -1.
So, the solution to the simultaneous equations is a = 1 and b = -1.
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