𝑦 = 𝑥 2 (√𝑥 + 1 3 ) at the point x=1 the square root is for x+1

The function you've given is a bit unclear due to formatting issues, but I'm assuming it's y = x^2 * sqrt(x+1) + 1/3.

To find the value of y at the point x=1, we substitute x=1 into the equation:

y = 1^2 * sqrt(1+1) + 1/3 y = 1 * sqrt(2) + 1/3 y = sqrt(2) + 1/3

So, at the point x=1, y = sqrt(2) + 1/3.