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What is the best method to prepare a sample of silver chloride?A Add silver nitrate to chlorine.B Add silver to hydrochloric acid.C Burn silver in chlorine.D Mix aqueous solutions of silver nitrate and sodium chloride.12:36 AMwhy the answer cannot be b12:36 AMd12:36 AMans12:36 AM

Question

What is the best method to prepare a sample of silver chloride?A Add silver nitrate to chlorine.B Add silver to hydrochloric acid.C Burn silver in chlorine.D Mix aqueous solutions of silver nitrate and sodium chloride.12:36 AMwhy the answer cannot be b12:36 AMd12:36 AMans12:36 AM

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Solution

To determine the best method to prepare a sample of silver chloride, let's analyze each option step by step:

A. Add silver nitrate to chlorine.

  • Silver nitrate (AgNO₃) and chlorine (Cl₂) do not directly react to form silver chloride (AgCl). This method is not suitable.

B. Add silver to hydrochloric acid.

  • Silver (Ag) is a relatively unreactive metal and does not react with hydrochloric acid (HCl) under normal conditions to form silver chloride. Therefore, this method is not effective.

C. Burn silver in chlorine.

  • Burning silver in chlorine gas can produce silver chloride, but this method is not practical for preparing a sample in a typical laboratory setting due to the need for chlorine gas and the difficulty in controlling the reaction.

D. Mix aqueous solutions of silver nitrate and sodium chloride.

  • When aqueous solutions of silver nitrate (AgNO₃) and sodium chloride (NaCl) are mixed, a precipitation reaction occurs, forming silver chloride (AgCl) as a white precipitate: AgNO3(aq)+NaCl(aq)AgCl(s)+NaNO3(aq) \text{AgNO}_3 (aq) + \text{NaCl} (aq) \rightarrow \text{AgCl} (s) + \text{NaNO}_3 (aq) This method is straightforward, safe, and commonly used in laboratories to prepare silver chloride.

Therefore, the best method to prepare a sample of silver chloride is option D: Mix aqueous solutions of silver nitrate and sodium chloride.

The answer cannot be B because silver does not react with hydrochloric acid to form silver chloride.

This problem has been solved

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