What will be the output of the following C code? #include <stdio.h> void main() { int x = 0; int *ptr = &x; printf("%d\n", *ptr); } Address of xJunk value0Run time error

The output of the given C code will be 0.

Here's the step by step explanation:

1. The integer variable 'x' is declared and initialized with the value 0.

2. A pointer variable '*ptr' is declared and it is assigned the address of 'x'. So, it points to the memory location of 'x'.

3. The printf function is used to print the value at the address pointed by 'ptr'. The '*' before 'ptr' is a dereference operator which is used to access the value at the address that 'ptr' is pointing to.

4. Since 'ptr' is pointing to 'x', and the value of 'x' is 0, the output of the printf function will be 0.