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If A= 4b`001x and B= 4b`1011, then result of A+B will bea.110xb.xxxxc.1111d.1100

Question

If A= 4b001x and B= 4b1011, then result of A+B will bea.110xb.xxxxc.1111d.1100

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Solution

The given numbers are in binary format.

A = 4b001x B = 4b1011

First, we need to clarify what 'x' stands for in A. If 'x' is a placeholder for an unknown, we can't proceed with the addition. However, if 'x' represents a binary digit (either 0 or 1), we can proceed with the addition.

Assuming 'x' is 0, A becomes 4b`0010.

Now, we can add A and B:

0010 (this is A)

  • 1011 (this is B)

1101

So, the result of A + B is 4b`1101.

Therefore, none of the options a, b, c, or d are correct. The correct answer is 4b`1101.

If 'x' is 1, A becomes 4b`0011.

Now, we can add A and B:

0011 (this is A)

  • 1011 (this is B)

1110

So, the result of A + B is 4b`1110.

Therefore, none of the options a, b, c, or d are correct. The correct answer is 4b`1110.

In conclusion, the result of A + B depends on the value of 'x'.

This problem has been solved

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