The selective complement operation is a bitwise operation where the bits of the second number decide whether to take the complement of the bits of the first number. If the bit in the second number is 1, the corresponding bit in the first number is complemented (flipped). If the bit in the second number is 0, the corresponding bit in the first number is left as is.

Given A=1100 and B=1010, let's perform the selective complement operation:

1. The first bit of B is 1, so we flip the first bit of A (from 1 to 0).
2. The second bit of B is 0, so we leave the second bit of A as is (1).
3. The third bit of B is 1, so we flip the third bit of A (from 0 to 1).
4. The fourth bit of B is 0, so we leave the fourth bit of A as is (0).

So, the result of the selective complement operation on A with B is 0110.

Question

The selective complement operation is a bitwise operation where the bits of the second number decide whether to take the complement of the bits of the first number. If the bit in the second number is 1, the corresponding bit in the first number is complemented (flipped). If the bit in the second number is 0, the corresponding bit in the first number is left as is.

Given A=1100 and B=1010, let's perform the selective complement operation:

1. The first bit of B is 1, so we flip the first bit of A (from 1 to 0).
2. The second bit of B is 0, so we leave the second bit of A as is (1).
3. The third bit of B is 1, so we flip the third bit of A (from 0 to 1).
4. The fourth bit of B is 0, so we leave the fourth bit of A as is (0).

So, the result of the selective complement operation on A with B is 0110.

Knowee AI · Accepted Answer

The selective complement operation is a bitwise operation where the bits of the second number decide whether to take the complement of the bits of the first number. If the bit in the second number is 1, the corresponding bit in the first number is complemented (flipped). If the bit in the second number is 0, the corresponding bit in the first number is left as is.

Given A=1100 and B=1010, let's perform the selective complement operation:

1. The first bit of B is 1, so we flip the first bit of A (from 1 to 0).
2. The second bit of B is 0, so we leave the second bit of A as is (1).
3. The third bit of B is 1, so we flip the third bit of A (from 0 to 1).
4. The fourth bit of B is 0, so we leave the fourth bit of A as is (0).

So, the result of the selective complement operation on A with B is 0110.

If A=1100, B=1010 then what will be the output of selective complement operation?*1 point1100011001011010

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