The given equation represents a type of radioactive decay known as beta decay. In beta decay, a neutron in the nucleus of an atom decays into a proton and an electron (the beta particle, represented here as 01e). The proton remains in the nucleus, increasing the atomic number by 1, while the electron is emitted.

The atomic number (the subscript) increases by 1, from 19 to 20. The atomic mass (the superscript) remains the same, 3719. Therefore, the product of this decay is an atom with atomic number 20 and atomic mass 3719.

Looking at the periodic table, the element with atomic number 20 is Argon (Ar). Therefore, the correct answer is 3719Ar, but with atomic number 20, so it should be 3720Ar.

However, none of the options A-D match this. There might be a mistake in the question or the provided options.

Question

The given equation represents a type of radioactive decay known as beta decay. In beta decay, a neutron in the nucleus of an atom decays into a proton and an electron (the beta particle, represented here as 01e). The proton remains in the nucleus, increasing the atomic number by 1, while the electron is emitted.

The atomic number (the subscript) increases by 1, from 19 to 20. The atomic mass (the superscript) remains the same, 3719. Therefore, the product of this decay is an atom with atomic number 20 and atomic mass 3719.

Looking at the periodic table, the element with atomic number 20 is Argon (Ar). Therefore, the correct answer is 3719Ar, but with atomic number 20, so it should be 3720Ar.

However, none of the options A-D match this. There might be a mistake in the question or the provided options.

Knowee AI · Accepted Answer

The given equation represents a type of radioactive decay known as beta decay. In beta decay, a neutron in the nucleus of an atom decays into a proton and an electron (the beta particle, represented here as 01e). The proton remains in the nucleus, increasing the atomic number by 1, while the electron is emitted.

The atomic number (the subscript) increases by 1, from 19 to 20. The atomic mass (the superscript) remains the same, 3719. Therefore, the product of this decay is an atom with atomic number 20 and atomic mass 3719.

Looking at the periodic table, the element with atomic number 20 is Argon (Ar). Therefore, the correct answer is 3719Ar, but with atomic number 20, so it should be 3720Ar.

However, none of the options A-D match this. There might be a mistake in the question or the provided options.

3719K → ___ + 01e A. 3718ArB. 3818ArC. 3918ArD. 4018Ar

Question

Solution

Similar Questions

Upgrade your grade with Knowee