The difference between the ages of two brothers is 8 years.If 12 years ago, the elder one was twice as old as his younger brother, what is the present age of the younger brother?
Question
The difference between the ages of two brothers is 8 years.If 12 years ago, the elder one was twice as old as his younger brother, what is the present age of the younger brother?
Solution
Let's denote the present age of the younger brother as X and the present age of the elder brother as X + 8 (since the difference between their ages is 8 years).
According to the problem, 12 years ago, the elder brother was twice as old as the younger one. So, we can write this as:
(X + 8) - 12 = 2 * (X - 12)
Solving this equation will give us the present age of the younger brother.
First, simplify the equation:
X - 4 = 2X - 24
Then, rearrange the equation to isolate X:
24 - 4 = 2X - X
Finally, solve for X:
X = 20
So, the present age of the younger brother is 20 years old.
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