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Rohan was 4 times as old as his son 6 years ago.After 6 years Rohan will be twice as old as his son.What is son's present age?10 years12 years14 years18 years

Question

Rohan was 4 times as old as his son 6 years ago.After 6 years Rohan will be twice as old as his son.What is son's present age?10 years12 years14 years18 years

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Solution 1

Let's denote Rohan's present age as R and his son's present age as S.

From the problem, we know that:

  1. Rohan was 4 times as old as his son 6 years ago. This can be written as: R - 6 = 4 * (S - 6)

  2. After 6 years, Rohan will be twice as old as his son. This can be written as: R + 6 = 2 * (S + 6)

Now we can solve these two equations to find the values of R and S.

From the first equation, we can express R in terms of S: R = 4S - 18

Substitute R in the second equation: 4S - 18 + 6 = 2S + 12

Simplify the equation: 2S = 24

So, S = 12

Therefore, Rohan's son is currently 12 years old.

This problem has been solved

Solution 2

Let's denote Rohan's present age as R and his son's present age as S.

From the problem, we know that:

  1. Rohan was 4 times as old as his son 6 years ago. This can be written as: R - 6 = 4 * (S - 6).

  2. After 6 years, Rohan will be twice as old as his son. This can be written as: R + 6 = 2 * (S + 6).

Now we can solve these two equations step by step:

From equation 1) we can express R as: R = 4S - 18.

We substitute R from equation 1) into equation 2):

4S - 18 + 6 = 2S + 12 4S - 2S = 12 + 18 2S = 30 S = 15

So, the son's present age is not listed in the options. There might be a mistake in the problem or the options.

This problem has been solved

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