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An organic chemistry student prepared 0.668 L of a cyclohexane-toluene solution at 29.0 °C by measuring out 222. mL of cyclohexane and 0.42 L of toluene and mixing them.Calculate the volume percent of cyclohexane in this solution.Be sure your answer has the right number of significant digits.

Question

An organic chemistry student prepared 0.668 L of a cyclohexane-toluene solution at 29.0 °C by measuring out 222. mL of cyclohexane and 0.42 L of toluene and mixing them.Calculate the volume percent of cyclohexane in this solution.Be sure your answer has the right number of significant digits.

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Solution

To calculate the volume percent of cyclohexane in the solution, you need to follow these steps:

  1. Convert all volumes to the same units. In this case, we will use liters. The volume of cyclohexane is already given in liters (0.222 L), and the volume of toluene is also given in liters (0.42 L).

  2. Add the volumes of cyclohexane and toluene to get the total volume of the solution. The total volume is 0.222 L (cyclohexane) + 0.42 L (toluene) = 0.642 L.

  3. Calculate the volume percent of cyclohexane by dividing the volume of cyclohexane by the total volume of the solution and then multiplying by 100 to get a percentage. The volume percent of cyclohexane is (0.222 L / 0.642 L) * 100 = 34.6%.

So, the volume percent of cyclohexane in the solution is 34.6%. This answer has three significant digits, which is appropriate given the number of significant digits in the original measurements.

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