The code you provided will result in a compile-time error. This is because in the printf statement, you are trying to multiply k * k (k + k) without an operator between k * k and (k + k).

In C, every operation that needs to be performed should be clearly specified. So, if you want to multiply k with k and then add it to the result of k + k, you should write it as k * k + k + k.

If you want to multiply k with the result of k * (k + k), you should write it as k * k * (k + k).

Without these corrections, the compiler will throw an error because it doesn't know what operation to perform.

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The code you provided will result in a compile-time error. This is because in the printf statement, you are trying to multiply k * k (k + k) without an operator between k * k and (k + k).

In C, every operation that needs to be performed should be clearly specified. So, if you want to multiply k with k and then add it to the result of k + k, you should write it as k * k + k + k.

If you want to multiply k with the result of k * (k + k), you should write it as k * k * (k + k).

Without these corrections, the compiler will throw an error because it doesn't know what operation to perform.

Knowee AI · Accepted Answer

The code you provided will result in a compile-time error. This is because in the printf statement, you are trying to multiply k * k (k + k) without an operator between k * k and (k + k).

In C, every operation that needs to be performed should be clearly specified. So, if you want to multiply k with k and then add it to the result of k + k, you should write it as k * k + k + k.

If you want to multiply k with the result of k * (k + k), you should write it as k * k * (k + k).

Without these corrections, the compiler will throw an error because it doesn't know what operation to perform.

at will be the output of the following code?1234567#include <stdio.h> int main() { for(int k = 0; k < 5; k++) { printf("%d ", k * k (k + k)); } return 0; }Marks : 1Negative Marks : 0Answer here0 1 4 9 160 2 4 6 81 4 9 16 25Compile time error

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