Samit measures the length of a spring and finds it is 0.15 m. He hangs a mass with a weight of 2 N from the end of the spring. He measures the length of the spring again and finds that it is now 0.17 m. Calculate the spring constant for this spring.
Question
Samit measures the length of a spring and finds it is 0.15 m. He hangs a mass with a weight of 2 N from the end of the spring. He measures the length of the spring again and finds that it is now 0.17 m. Calculate the spring constant for this spring.
Solution
To calculate the spring constant (k), we can use Hooke's Law, which states that the force (F) exerted by a spring is equal to the displacement (x) it experiences times the spring constant (k). This can be written as F = kx.
In this case, the displacement of the spring is the difference in length before and after the weight was added. So, x = 0.17 m - 0.15 m = 0.02 m.
The force exerted on the spring is equal to the weight hung from it, which is 2 N.
We can now substitute these values into Hooke's Law to find the spring constant:
2 N = k * 0.02 m
Solving for k gives us k = 2 N / 0.02 m = 100 N/m.
So, the spring constant for this spring is 100 N/m.
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