A force of 5 N is applied to a spring, causing it to stretch from a length of 0.1 m, to a length of 0.15 m.What is the spring constant of the spring?
Question
A force of 5 N is applied to a spring, causing it to stretch from a length of 0.1 m, to a length of 0.15 m.What is the spring constant of the spring?
Solution
The spring constant (k) can be calculated using Hooke's Law, which states that the force (F) exerted by a spring is equal to the displacement (x) it experiences times the spring constant (k). The formula is:
F = kx
We can rearrange this formula to solve for k:
k = F/x
In this case, the force (F) is 5 N and the displacement (x) is the change in length of the spring, which is 0.15 m - 0.1 m = 0.05 m.
So, we can substitute these values into the formula:
k = 5 N / 0.05 m = 100 N/m
So, the spring constant of the spring is 100 N/m.
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