Let's solve this step by step:

1. Let's assume the two consecutive numbers are n and n+1.

2. According to the problem, the difference between the squares of these two numbers is 35. So, we can write the equation as: (n+1)^2 - n^2 = 35.

3. Simplifying the equation, we get: n^2 + 2n + 1 - n^2 = 35.

4. Further simplifying, we get: 2n + 1 = 35.

5. Solving for n, we get: n = (35 - 1) / 2 = 17.

So, the two consecutive numbers are 17 and 18. Therefore, the correct option is "17 & 18".

Question

Let's solve this step by step:

1. Let's assume the two consecutive numbers are n and n+1.

2. According to the problem, the difference between the squares of these two numbers is 35. So, we can write the equation as: (n+1)^2 - n^2 = 35.

3. Simplifying the equation, we get: n^2 + 2n + 1 - n^2 = 35.

4. Further simplifying, we get: 2n + 1 = 35.

5. Solving for n, we get: n = (35 - 1) / 2 = 17.

So, the two consecutive numbers are 17 and 18. Therefore, the correct option is "17 & 18".

Knowee AI · Accepted Answer

Let's solve this step by step:

1. Let's assume the two consecutive numbers are n and n+1.

2. According to the problem, the difference between the squares of these two numbers is 35. So, we can write the equation as: (n+1)^2 - n^2 = 35.

3. Simplifying the equation, we get: n^2 + 2n + 1 - n^2 = 35.

4. Further simplifying, we get: 2n + 1 = 35.

5. Solving for n, we get: n = (35 - 1) / 2 = 17.

So, the two consecutive numbers are 17 and 18. Therefore, the correct option is "17 & 18".

Select the correct answerThe difference between the squares of two consecutive numbers is 35. The numbers are?Options19&2018&1716&1817&2017&18