Let's denote the original speed as x kmph and the distance as d km.

From the first condition, we know that the time taken to cover the distance at the original speed (d/x hours) minus the time taken to cover the same distance at a speed 3 kmph faster (d/(x+3) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the equation: d/x - d/(x+3) = 2/3.

From the second condition, we know that the time taken to cover the distance at the original speed (d/x hours) plus the time taken to cover the same distance at a speed 2 kmph slower (d/(x-2) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the second equation: d/x - d/(x-2) = -2/3.

Solving these two equations simultaneously, we get x = 15 kmph and d = 60 km.

So, the distance covered by the man is 60 km.

Question

Let's denote the original speed as x kmph and the distance as d km.

From the first condition, we know that the time taken to cover the distance at the original speed (d/x hours) minus the time taken to cover the same distance at a speed 3 kmph faster (d/(x+3) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the equation: d/x - d/(x+3) = 2/3.

From the second condition, we know that the time taken to cover the distance at the original speed (d/x hours) plus the time taken to cover the same distance at a speed 2 kmph slower (d/(x-2) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the second equation: d/x - d/(x-2) = -2/3.

Solving these two equations simultaneously, we get x = 15 kmph and d = 60 km.

So, the distance covered by the man is 60 km.

Knowee AI · Accepted Answer

Let's denote the original speed as x kmph and the distance as d km.

From the first condition, we know that the time taken to cover the distance at the original speed (d/x hours) minus the time taken to cover the same distance at a speed 3 kmph faster (d/(x+3) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the equation: d/x - d/(x+3) = 2/3.

From the second condition, we know that the time taken to cover the distance at the original speed (d/x hours) plus the time taken to cover the same distance at a speed 2 kmph slower (d/(x-2) hours) equals 40 minutes, which is 40/60 = 2/3 hours.

So, we have the second equation: d/x - d/(x-2) = -2/3.

Solving these two equations simultaneously, we get x = 15 kmph and d = 60 km.

So, the distance covered by the man is 60 km.

A man covers a certain distance on scooter. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is :

Question

Solution

Similar Questions

Upgrade your grade with Knowee