solve the equationdy/dx - tany/(1+x) =(1+x)exsecy

solve the equationdy/dx - tany/(1+x) =(1+x)exsecy

Find an equation of the tangent line to the graph of te function y = 1+ln xex atthe point where x = 1

Solve ∫[tanx−−−−√+cotx−−−−√]dx

Find y' if y = ln⁡|sec⁡ x + tan⁡ x |*sec⁡xsecx tanxsec^2x tan xsec^2 x

What is the equation of the tangent to the curve:𝑦=𝑥2−1𝑥2+1y= x 2 +1x 2 −1​ y, equals, start fraction, x, squared, minus, 1, divided by, x, squared, plus, 1, end fractionat the point where 𝑥=1x=1x, equals, 1?