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Tank A holds 5,032 ml of water and Tank B holds 9,508 ml of water. The water from both tanks is poured into Tank C which is empty. What is the volume of water in Tank C, rounded to the nearest hundred ml?

Question

Tank A holds 5,032 ml of water and Tank B holds 9,508 ml of water. The water from both tanks is poured into Tank C which is empty. What is the volume of water in Tank C, rounded to the nearest hundred ml?

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Solution

To solve this problem, follow these steps:

  1. Identify the volume of water in each tank. Tank A holds 5,032 ml of water and Tank B holds 9,508 ml of water.

  2. Add the volumes of water from both tanks together. This is done by adding 5,032 ml (from Tank A) and 9,508 ml (from Tank B).

  3. The sum of 5,032 ml and 9,508 ml is 14,540 ml. This is the total volume of water that is poured into Tank C.

  4. The problem asks for the volume of water in Tank C rounded to the nearest hundred ml. To do this, look at the tens place of the number 14,540. The tens place is 4. If this number is 5 or more, round up. If it is less than 5, round down. In this case, 4 is less than 5, so round down.

  5. Therefore, the volume of water in Tank C, rounded to the nearest hundred ml, is 14,500 ml.

This problem has been solved

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