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The ratio of the volume of water in Jug A to the volume of water in Jug B is 3 : 5.Jug A contains 900 ml of water.What is the volume of water in Jug B in milliliters? milliliters

Question

The ratio of the volume of water in Jug A to the volume of water in Jug B is 3 : 5.Jug A contains 900 ml of water.What is the volume of water in Jug B in milliliters? milliliters

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Solution

To solve this problem, we can use the concept of ratios.

Step 1: Understand the ratio. The ratio of the volume of water in Jug A to Jug B is 3:5. This means for every 3 parts of water in Jug A, there are 5 parts of water in Jug B.

Step 2: Find the value of each part. We know that Jug A contains 900 ml of water. According to the ratio, this 900 ml represents 3 parts. So, to find the value of each part, we divide 900 ml by 3.

900 ml ÷ 3 = 300 ml.

So, each part is equal to 300 ml.

Step 3: Find the volume of water in Jug B. According to the ratio, Jug B contains 5 parts of water. Now that we know each part is 300 ml, we can find the total volume in Jug B by multiplying 5 (parts) by 300 ml (each part).

5 * 300 ml = 1500 ml.

So, Jug B contains 1500 ml of water.

This problem has been solved

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