TABLE NAME: AGG_ORDERS (Table names are case sensitive)FIELD NAMES: ord_no, purchase_amt, ord_date, cust_id, salesman_idWrite a query to find the maximum purchase amount made by each customer from the 'AGG_ORDERS' table.

Given a table with order details. Please find the table details and sample data below.TABLE NAME: AGG_ORDERS (Table names are case sensitive)FIELD NAMES: ord_no, purchase_amt, ord_date, cust_id, salesman_idWrite a query to find the maximum purchase amount made by each customer from the 'AGG_ORDERS' table.Note: The required input details will be populated in the backend.This is only a sample data.Input format :The input tables are already prepopulated, as given in the problem statement.Output format :The output should display the customer ID and the corresponding maximum purchase amount as shown below.Customer_ID Amount123 788.50278 975.50367 3000.00456 2065.50567 123.25789 2500.00

Given a table with order details. Please find the table details and sample data below.TABLE NAME: AGG_ORDERS (Table names are case sensitive)FIELD NAMES: ord_no, purchase_amt, ord_date, cust_id, salesman_id

From the following table, write an SQL query to retrieve the customer ID, order date, and maximum purchase amount for each customer on each order date where the maximum purchase amount exceeds 2000.00. The results should be sorted by customer ID.

Query the customer_number from the orders table for the customer who has placed the largest number of orders.It is guaranteed that exactly one customer will have placed more orders than any other customer.The orders table is defined as follows:ColumnTypeorder_number (PK)intcustomer_numberintorder_datedaterequired_datedateshipped_datedatestatuschar(15)commentchar(200)Sample Inputorder_numbercustomer_numberorder_daterequired_dateshipped_date112017-04-092017-04-132017-04-12222017-04-152017-04-202017-04-18332017-04-162017-04-252017-04-20442017-04-182017-04-282017-04-25Sample Outputcustomer_number3ExplanationThe customer with number '3' has two orders, which is greater than either customer '1' or '2' because each of them only has one order.So the result is customer_number '3'. Follow up: What if more than one customer have the largest number of orders, can you find all the customer_number in this case?Optionsselect customer_numberfrom ( select customer_number, count(*) as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_number select customer_number, count(*) as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_numberfrom ( select customer_number, count(*) as cnt from orders group by customer_number) as elimit 1;select customer_numberfrom ( select customer_number, count(*) as cnt group by customer_number) as eorder by e.cnt desclimit 1;

Select the correct answerConsider the following SQL query: SELECT customer_id, MAX(total_amount) AS max_amount FROM Orders GROUP BY customer_id HAVING COUNT(*) > 1;What will be the output of this query?OptionsThe customer IDs and the maximum order amount for customers who have placed more than one order.An error because the HAVING clause is used without an aggregate function in the SELECT clause. An error because the GROUP BY clause is not properly used.The customer IDs and the average order amount for customers who have placed more than one order.