Query the customer_number from the orders table for the customer who has placed the largest number of orders.It is guaranteed that exactly one customer will have placed more orders than any other customer.The orders table is defined as follows:ColumnTypeorder_number (PK)intcustomer_numberintorder_datedaterequired_datedateshipped_datedatestatuschar(15)commentchar(200)Sample Inputorder_numbercustomer_numberorder_daterequired_dateshipped_date112017-04-092017-04-132017-04-12222017-04-152017-04-202017-04-18332017-04-162017-04-252017-04-20442017-04-182017-04-282017-04-25Sample Outputcustomer_number3ExplanationThe customer with number '3' has two orders, which is greater than either customer '1' or '2' because each of them only has one order.So the result is customer_number '3'. Follow up: What if more than one customer have the largest number of orders, can you find all the customer_number in this case?Optionsselect customer_numberfrom ( select customer_number, count(*) as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_number select customer_number, count(*) as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_numberfrom ( select customer_number, count(*) as cnt from orders group by customer_number) as elimit 1;select customer_numberfrom ( select customer_number, count(*) as cnt group by customer_number) as eorder by e.cnt desclimit 1;
Question
Query the customer_number from the orders table for the customer who has placed the largest number of orders.It is guaranteed that exactly one customer will have placed more orders than any other customer.The orders table is defined as follows:ColumnTypeorder_number (PK)intcustomer_numberintorder_datedaterequired_datedateshipped_datedatestatuschar(15)commentchar(200)Sample Inputorder_numbercustomer_numberorder_daterequired_dateshipped_date112017-04-092017-04-132017-04-12222017-04-152017-04-202017-04-18332017-04-162017-04-252017-04-20442017-04-182017-04-282017-04-25Sample Outputcustomer_number3ExplanationThe customer with number '3' has two orders, which is greater than either customer '1' or '2' because each of them only has one order.So the result is customer_number '3'. Follow up: What if more than one customer have the largest number of orders, can you find all the customer_number in this case?Optionsselect customer_numberfrom ( select customer_number, count() as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_number select customer_number, count() as cnt from orders group by customer_number) as eorder by e.cnt desclimit 1;select customer_numberfrom ( select customer_number, count() as cnt from orders group by customer_number) as elimit 1;select customer_numberfrom ( select customer_number, count() as cnt group by customer_number) as eorder by e.cnt desclimit 1;
Solution
The correct SQL query to find the customer who has placed the largest number of orders is:
SELECT customer_number
FROM (
SELECT customer_number, COUNT(*) as cnt
FROM orders
GROUP BY customer_number
) as e
ORDER BY e.cnt DESC
LIMIT 1;
This query works by first creating a subquery that groups the orders table by customer_number and counts the number of orders each customer has placed. This subquery is then ordered by the count in descending order, and the top result (the customer with the most orders) is selected.
If more than one customer have the largest number of orders, you can modify the query to find all these customers. However, this requires a bit more complex query because you need to compare the count of orders for each customer with the maximum count of orders. Here is how you can do it:
SELECT customer_number
FROM (
SELECT customer_number, COUNT(*) as cnt
FROM orders
GROUP BY customer_number
) as e
WHERE e.cnt = (
SELECT MAX(cnt)
FROM (
SELECT COUNT(*) as cnt
FROM orders
GROUP BY customer_number
) as f
);
This query first calculates the count of orders for each customer, then it compares this count with the maximum count of orders (calculated in a separate subquery), and selects the customers where these two values match.
Similar Questions
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