A, B and C can do a piece of work in 12 , 24 and 36 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Question
A, B and C can do a piece of work in 12 , 24 and 36 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Solution
Sure, let's solve this step by step.
Step 1: First, we need to find out the one day's work of A, B and C.
A's one day work = 1/12 B's one day work = 1/24 C's one day work = 1/36
Step 2: Now, let's find out the combined work of A, B and C in one day.
A, B and C's one day work = 1/12 + 1/24 + 1/36 = 1/6
Step 3: Now, let's find out the work done by A in two days and by A, B and C on the third day.
Two days work of A = 2 * (1/12) = 1/6 Third day's work (A, B and C) = 1/6
So, total work done in 3 days = 1/6 + 1/6 = 1/3
Step 4: Now, let's find out the total number of days A can complete the work if he is assisted by B and C on every third day.
Since 1/3 of the work is done in 3 days, the whole work will be done in 3 * 3 = 9 days.
So, A can complete the work in 9 days if he is assisted by B and C on every third day.
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