A, B and C can do a piece of work in 12, 24 and 48 days respectively. In how many days A can do the work if he is assisted by B and C on every fourth day?radio_button_unchecked9 daysradio_button_unchecked10.5 daysradio_button_unchecked11.5 daysradio_button_unchecked12 days

Let's solve this step by step:

Step 1: First, we need to find out the one day's work of A, B, and C.

A's one day's work = 1/12 B's one day's work = 1/24 C's one day's work = 1/48

Step 2: Now, let's find out the combined work of A, B, and C in one day.

A, B, and C's one day's work = 1/12 + 1/24 + 1/48 = 1/8

Step 3: Now, let's find out the work done by A in three days and by A, B, and C on the fourth day.

Work done in 4 days = 3*(1/12) + 1*(1/8) = 5/24

Step 4: Now, let's find out the number of such 4-day work cycles that can be completed, and the remaining work if any.

Number of 4-day cycles = 1/(5/24) = 4.8 cycles. This means that full 4 cycles can be completed and there will be 0.8 of a cycle remaining.

Step 5: In the remaining 0.8 cycle, A will work alone. So, the time taken for this remaining work = 0.8 * 4 = 3.2 days

Step 6: So, the total time taken = 4 full cycles * 4 days/cycle + 3.2 days = 16 + 3.2 = 19.2 days

So, A can do the work in approximately 19.2 days if he is assisted by B and C on every fourth day. However, this option is not given in the choices. There might be a mistake in the question or the options provided.