Knowee
Questions
Features
Study Tools

Jacobian of u=y-x/1+xy and v=tan-1y - tan-1x . Find del(u,v)/del(x,y)

Question

Jacobian of u=y-x/1+xy and v=tan-1y - tan-1x . Find del(u,v)/del(x,y)

🧐 Not the exact question you are looking for?Go ask a question

Solution

The Jacobian matrix of a vector-valued function is a matrix that contains all of the first order partial derivatives of the function. In this case, we have the functions u = y - x/(1 + xy) and v = arctan(y) - arctan(x).

The Jacobian matrix J of these functions with respect to x and y is given by:

J = [du/dx, du/dy] [dv/dx, dv/dy]

We need to compute each of these partial derivatives.

  1. Compute du/dx:

du/dx = -1/(1 + xy) + x*(-y)/((1 + xy)^2)

  1. Compute du/dy:

du/dy = 1 - x^2/((1 + xy)^2)

  1. Compute dv/dx:

dv/dx = -1/(1 + x^2)

  1. Compute dv/dy:

dv/dy = 1/(1 + y^2)

So, the Jacobian matrix is:

J = [-1/(1 + xy) + x*(-y)/((1 + xy)^2), 1 - x^2/((1 + xy)^2)] [-1/(1 + x^2), 1/(1 + y^2)]

This problem has been solved

Similar Questions

Jacobian of x=e^u cosv and y=e^u sinv . Find del(u,v)/del(x,y)

If u=tan-1 ((x2+y2)/(x+y)), then x ∂u/∂x+y ∂u/∂y=

If u=tan-12+y2)/(x+y)), then x ∂u/∂x+y ∂u/∂y=

solve the equationdy/dx - tany/(1+x) =(1+x)exsecy

find the dy/dx of xy^3 cos x + x^2y = 1 with step by step working out

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.