Jacobian of u=y-x/1+xy and v=tan-1y - tan-1x . Find del(u,v)/del(x,y)
Question
Jacobian of u=y-x/1+xy and v=tan-1y - tan-1x . Find del(u,v)/del(x,y)
Solution
The Jacobian matrix of a vector-valued function is a matrix that contains all of the first order partial derivatives of the function. In this case, we have the functions u = y - x/(1 + xy) and v = arctan(y) - arctan(x).
The Jacobian matrix J of these functions with respect to x and y is given by:
J = [du/dx, du/dy] [dv/dx, dv/dy]
We need to compute each of these partial derivatives.
- Compute du/dx:
du/dx = -1/(1 + xy) + x*(-y)/((1 + xy)^2)
- Compute du/dy:
du/dy = 1 - x^2/((1 + xy)^2)
- Compute dv/dx:
dv/dx = -1/(1 + x^2)
- Compute dv/dy:
dv/dy = 1/(1 + y^2)
So, the Jacobian matrix is:
J = [-1/(1 + xy) + x*(-y)/((1 + xy)^2), 1 - x^2/((1 + xy)^2)] [-1/(1 + x^2), 1/(1 + y^2)]
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