Let Y be a random variable as followsP(Y=-6) = 0.1P(Y=-1) = 0.1P(Y=0) = 0.1P(Y=1) = cthen what is the value of c (give your answer to 1dp)?
Question
Let Y be a random variable as followsP(Y=-6) = 0.1P(Y=-1) = 0.1P(Y=0) = 0.1P(Y=1) = cthen what is the value of c (give your answer to 1dp)?
Solution
The sum of probabilities for all possible outcomes of a random variable must equal 1.
Given that P(Y=-6) = 0.1, P(Y=-1) = 0.1, and P(Y=0) = 0.1, we can add these probabilities together to get 0.3.
Therefore, the probability of the remaining outcome, P(Y=1) = c, must be such that the total probability is 1.
So, we can calculate c as follows:
c = 1 - 0.3 = 0.7
Therefore, the value of c is 0.7 (to 1 decimal place).
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