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Write a script that generates the assembly code (Intel syntax) of a C code and save it in an output file.The C file name will be saved in the variable $CFILE.The output file should be named the same as the C file, but with the extension .s instead of .c.Example: if the C file is main.c, the output file should be main.s

Question

Write a script that generates the assembly code (Intel syntax) of a C code and save it in an output file.The C file name will be saved in the variable $CFILE.The output file should be named the same as the C file, but with the extension .s instead of .c.Example: if the C file is main.c, the output file should be main.s

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Solution

Sure, here is a bash script that will do the job:

#!/bin/bash

# Check if CFILE variable is set
if [ -z "$CFILE" ]
then
  echo "CFILE variable is not set."
  exit 1
fi

# Check if the C file exists
if [ ! -f "$CFILE" ]
then
  echo "File $CFILE does not exist."
  exit 1
fi

# Generate the output file name by replacing .c with .s
OUTFILE="${CFILE%.c}.s"

# Generate the assembly code
gcc -S -masm=intel $CFILE -o $OUTFILE

echo "Assembly code has been saved in $OUTFILE."

This script first checks if the CFILE variable is set and if the C file exists. If both checks pass, it generates the output file name by replacing the .c extension with .s in the CFILE variable. Then it uses gcc to generate the assembly code with Intel syntax and save it in the output file. Finally, it prints a message indicating that the assembly code has been saved in the output file.

This problem has been solved

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