Knowee
Questions
Features
Study Tools

You are the new technology administrator of a college responsible for managing student data. The college offers four courses with their respective details:Science (Course Code: 1001, Credits: 10)Maths (Course Code: 1002, Credits: 5)Literature (Course Code: 1003, Credits: 5)Philosophy (Course Code: 1004, Credits: 1)Each student must enroll in exactly three courses, and their performance is graded from 0 to 10.Complete the C code for the program, by writing the code for the function float calculate_gpa(student s);This function takes as an input the struct student variable of a student s, which contains all the informationabout the courses the student s took and her grades in the courses.You have to return the total cgpa of the student as the output.Input:The first line contains the number of students, n.The next n lines contain information about each student in the following order:NameCourse Code 1Marks 1Course Code 2Marks 2Course Code 3Marks 3Output:The names and CGPAs (to a single decimal point) of students, each line in the following format:Name CGPAInput11Bala 1001 9 1002 10 1003 8OutputBala 9.0ExplanationBala has scored9/10 in 1001 (10 Credits)10/10 in 1002 (5 Credits)8/10 in 1003 (5 Credits)So his total cgpa is  9∗10+10∗5+8∗5/10+5+5=180/20=9.0

Question

You are the new technology administrator of a college responsible for managing student data. The college offers four courses with their respective details:Science (Course Code: 1001, Credits: 10)Maths (Course Code: 1002, Credits: 5)Literature (Course Code: 1003, Credits: 5)Philosophy (Course Code: 1004, Credits: 1)Each student must enroll in exactly three courses, and their performance is graded from 0 to 10.Complete the C code for the program, by writing the code for the function float calculate_gpa(student s);This function takes as an input the struct student variable of a student s, which contains all the informationabout the courses the student s took and her grades in the courses.You have to return the total cgpa of the student as the output.Input:The first line contains the number of students, n.The next n lines contain information about each student in the following order:NameCourse Code 1Marks 1Course Code 2Marks 2Course Code 3Marks 3Output:The names and CGPAs (to a single decimal point) of students, each line in the following format:Name CGPAInput11Bala 1001 9 1002 10 1003 8OutputBala 9.0ExplanationBala has scored9/10 in 1001 (10 Credits)10/10 in 1002 (5 Credits)8/10 in 1003 (5 Credits)So his total cgpa is  9∗10+10∗5+8∗5/10+5+5=180/20=9.0

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The problem is asking to write a C function that calculates the GPA of a student. The GPA is calculated by multiplying the grade of each course by the credits of the course, summing these values, and then dividing by the total number of credits.

Here is a possible implementation of the function:

#include <stdio.h>

typedef struct {
    char name[50];
    int course_code[3];
    int marks[3];
} student;

float calculate_gpa(student s) {
    int total_credits = 0;
    int total_marks = 0;
    for (int i = 0; i < 3; i++) {
        int credits;
        switch (s.course_code[i]) {
            case 1001:
                credits = 10;
                break;
            case 1002:
                credits = 5;
                break;
            case 1003:
                credits = 5;
                break;
            case 1004:
                credits = 1;
                break;
        }
        total_credits += credits;
        total_marks += s.marks[i] * credits;
    }
    return (float)total_marks / total_credits;
}

int main() {
    student s = {"Bala", {1001, 1002, 1003}, {9, 10, 8}};
    printf("%s %.1f\n", s.name, calculate_gpa(s));
    return 0;
}

This code first defines a student struct that contains the name, course codes, and marks of a student. The calculate_gpa function then calculates the GPA by iterating over the courses, determining the credits for each course, and summing the product of the marks and credits. The function finally returns the total marks divided by the total credits. The main function then tests this function with a sample student.

This problem has been solved

Solution 2

The problem is asking to write a C function that calculates the CGPA of a student. The CGPA is calculated by summing up the product of the grade and the credit of each course the student took, then dividing it by the total credits of the courses.

Here is the C code for the function:

#include <stdio.h>

typedef struct {
    char name[50];
    int course_code[3];
    int marks[3];
} student;

float calculate_gpa(student s) {
    int total_credits = 0;
    int total_marks = 0;
    for(int i = 0; i < 3; i++) {
        int credits;
        switch(s.course_code[i]) {
            case 1001: credits = 10; break;

This problem has been solved

Similar Questions

The basic formula to calculate a student's GPA is the:A.addition of all grade points in completed courses divided by the number of classes completed.B.addition of all grade points in completed courses and subtraction of all uncompleted courses.C.multiplication of all grade points in completed classes and subtraction of all uncompleted courses.D.multiplication of all grade points in completed courses divided by the number of classes completed.

Scholarship Scheme Calculation ProgramYou are tasked with developing a scholarship scheme calculation program for a university. The program will determine the amount of fees to be waived for students based on their academic excellence and sports achievements. Requirements:Student Class Hierarchy: Create an abstract class Student with the following attributes:regNo (Registration Number)name (Name of the student)FEES (Static constant representing the total fees, which is set to 2,00,000)Implement an abstract method calculateFees() in the Student class.Implement two subclasses of Student:AcademicExcellence: Contains attributes:CGPA (Grade Point Average)AI (Annual Income)Sports: Contains attributes:sportLevel (Level of sports achievement: State, National, International)noOfGamesPlayed (Number of games played by the student)Scholarship Criteria: For AcademicExcellence:If CGPA is 'S' and AI is less than 30,000, the entire fees will be waived.If CGPA is 'A' and AI is between 31,000 to 1 lakh, 50% of the fees will be waived.Otherwise, no fees will be waived.For Sports:If the student is an international player and has played more than 2 games, the entire fees will be waived.If the student is a national player and has played more than 10 games, 50% of the fees will be waived.If the student is a state player and has played between 20 to 30 games, 25% of the fees will be waived.Otherwise, no fees will be waived.Input/Output Format: Prompt the user to input the number of students.For each student, ask whether they are applying based on academic excellence or sports.Depending on the choice:For AcademicExcellence: Ask for regNo, name, CGPA, and AI.For Sports: Ask for regNo, name, sportLevel, and noOfGamesPlayed.Calculate and display the fees to be paid by each student based on the scholarship criteria.

DescriptionAll the first-year students in the computer science (CS) department in a university take both the courses (i) AI and (ii) ML. Students from other departments (non-CS students) can also take one of these two courses, but not both. Students who fail in a course get an F grade; others pass and are awarded A or B or C grades depending on their performance. The following are some additional facts about the number of students who took these two courses this year and the grades they obtained.The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.The number of non-CS students who took either AI or ML was equal to the number of CS students.The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.No CS student failed in AI, while no non-CS student got an A grade in AI.The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 :1.30 students failed in ML.How many students got A grade in AI?Please select your Answer.63998442

You have a class consisting of 5 students, each with a unique name and their respective marks. As the end of the semester approaches, you decide to assess the performance of your students and recognize their academic achievements.You write a Python program to categorize the students into different grades based on their marks. The program utilizes a Grade_analyzer class to represent each student and a StudentGradeAnalyzer function to analyze their grades. The function iterates through the list of students, calculates their grades and returns a dictionary containing the count of students in each grade.For grading:Students scoring between 80-100 will be in Grade A.Students scoring between 70-80 will be in Grade B.Students scoring between 60-70 will be in Grade C.Students scoring between 50-60 will be in Grade D.Students scoring below 50 will be in Grade E.Constraints:Input Format:5 lines of input, each line containing name and marks of each student.Ouptut Format:Should display items in dictionary which is holding Grades as keys and count of students falling under the grades as values.Example:Input:john 78missy 89sheldon 90mary 45meemaw 67Output:('A', 2)('B', 1)('C', 1)('D', 0)('E', 1)Explanation:input:--------Space saperated input name and marks for all the 5 students.john 78-->78 Falls into a range 70-80 so count of grade 'B' should be increased to 1.missy 89-->89 Falls into a range 80-100 so count of grade 'A' should be increased to 1.sheldon 90-->90 Falls into a range 80-100 so count of grade 'A' should be increased to 2.mary 45-->45 is less than 50 so count of grade 'E' should be increased to 1.meemaw 67-->67 Falls into a range 60-70 so count of grade 'C' should be increased to 1.

.Write a Python program to store marks scored in subject “Fundamental of DataStructure” by N students in the class and perform different operations.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.