DescriptionAll the first-year students in the computer science (CS) department in a university take both the courses (i) AI and (ii) ML. Students from other departments (non-CS students) can also take one of these two courses, but not both. Students who fail in a course get an F grade; others pass and are awarded A or B or C grades depending on their performance. The following are some additional facts about the number of students who took these two courses this year and the grades they obtained.The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.The number of non-CS students who took either AI or ML was equal to the number of CS students.The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.No CS student failed in AI, while no non-CS student got an A grade in AI.The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 :1.30 students failed in ML.How many students got A grade in AI?Please select your Answer.63998442
Question
DescriptionAll the first-year students in the computer science (CS) department in a university take both the courses (i) AI and (ii) ML. Students from other departments (non-CS students) can also take one of these two courses, but not both. Students who fail in a course get an F grade; others pass and are awarded A or B or C grades depending on their performance. The following are some additional facts about the number of students who took these two courses this year and the grades they obtained.The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.The number of non-CS students who took either AI or ML was equal to the number of CS students.The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.No CS student failed in AI, while no non-CS student got an A grade in AI.The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 :1.30 students failed in ML.How many students got A grade in AI?Please select your Answer.63998442
Solution
The problem is a bit complex, but let's break it down step by step.
-
Let's denote the number of non-CS students who took AI as 2x and those who took ML as 5x.
-
It's given that the total number of non-CS students (2x + 5x = 7x) is equal to the number of CS students. Let's denote the number of CS students as y. So, we have 7x = y.
-
The number of non-CS students who failed in both courses is the same and is equal to the number of CS students who got a C grade in ML. Let's denote this number as z. So, we have 2z = y.
-
From the above two equations, we can conclude that 2z = 7x.
-
It's given that the ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3:1. So, z = 3f, where f is the number of CS students who failed.
-
It's given that 30 students failed in ML. Since no CS student failed in AI, all the CS students who failed must have failed in ML. So, f = 30.
-
Substituting f = 30 in z = 3f, we get z = 90.
-
Substituting z = 90 in 2z = 7x, we get x = 180/7.
-
The number of CS students who got A, B and C grades respectively in AI were in the ratio 3:5:2. Since the number of students who got C grade is z = 90, the total number of CS students who passed AI is 90 * 10/2 = 450.
-
The number of students who got A grade in AI is 450 * 3/10 = 135.
So, 135 students got A grade in AI.
Similar Questions
You are the new technology administrator of a college responsible for managing student data. The college offers four courses with their respective details:Science (Course Code: 1001, Credits: 10)Maths (Course Code: 1002, Credits: 5)Literature (Course Code: 1003, Credits: 5)Philosophy (Course Code: 1004, Credits: 1)Each student must enroll in exactly three courses, and their performance is graded from 0 to 10.Complete the C code for the program, by writing the code for the function float calculate_gpa(student s);This function takes as an input the struct student variable of a student s, which contains all the informationabout the courses the student s took and her grades in the courses.You have to return the total cgpa of the student as the output.Input:The first line contains the number of students, n.The next n lines contain information about each student in the following order:NameCourse Code 1Marks 1Course Code 2Marks 2Course Code 3Marks 3Output:The names and CGPAs (to a single decimal point) of students, each line in the following format:Name CGPAInput11Bala 1001 9 1002 10 1003 8OutputBala 9.0ExplanationBala has scored9/10 in 1001 (10 Credits)10/10 in 1002 (5 Credits)8/10 in 1003 (5 Credits)So his total cgpa is 9∗10+10∗5+8∗5/10+5+5=180/20=9.0
In a high school, students have the option to choose two elective courses: Photography and Music. All students in the Art Department are required to take both courses, while students from other departments can select one of the two options. Grades are given based on performance with A, B and C representing different levels of achievement and F for failure. Consider the following additional information about the number of students who took these courses this year and the grades they obtained:(i) The ratio of the number of non-Art Department students who chose Photography to that of those who chose Music was 3 : 4.(ii) The total number of non-Art Department students who took either Photography or Music was equal to the number of Art Department students.(iii) The number of non-Art Department students who failed in both Photography and Music courses was the same, and this total was equivalent to the number of Art Department students who received grade C in Music.(iv) Among the students who passed Music courses, 60% achieved grade B. However, while the numbers of students who received grades A and C were equal for Photography, the ratio for Music was 24 : 7.(v) No Art Department student failed in the Photography course, and no non-Art Department student received grade A in Photography.(vi) The ratio of the numbers of Art Department students who received grades A, B and C in Photography was 3 : 5 : 2, while for Music, the ratio was 4 : 5 : 1.(vii) The ratio of the total number of non-Art Department students failing in either of the two courses to the number of Art Department students failing in either of the two courses was 2 : 1.(viii) A total of 20 students failed in the Music course.Question No. 1What is the number of non-Art Music students who got grade C?8101416
A student got 42% marks and has secured 12 marks more than the minimum passing marks. Another student got 45% has obtained 30 marks more than the minimum passing marks. The maximum marks are
What is necessary to succeed in learning C according to the course?
As a python student, write a program using functions and conditions to display the grades that the students will be receiving. The grades are:90% - 100% Grade is A 80% - 89% Grade is B70% - 79% Grade is C 60% - 69% Grade is D 50% - 59% Grade is E <50% Fail
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.