Sure, let's solve this step by step.

First, we need to understand the relationship between the angles given and the angle we want to find the sine of.

We know that sin(180° - θ) = sinθ and cos(180° - θ) = -cosθ.

So, sin130° = sin(180° - 50°) = sin50° = p.

Also, cos110° = cos(180° - 70°) = -cos70°. But cos70° = sin(90° - 70°) = sin20°.

However, we don't have a direct relationship to express sin20° in terms of p or q.

Therefore, we can't express sin130° only in terms of p and q.

Question

Sure, let's solve this step by step.

First, we need to understand the relationship between the angles given and the angle we want to find the sine of.

We know that sin(180° - θ) = sinθ and cos(180° - θ) = -cosθ.

So, sin130° = sin(180° - 50°) = sin50° = p.

Also, cos110° = cos(180° - 70°) = -cos70°. But cos70° = sin(90° - 70°) = sin20°.

However, we don't have a direct relationship to express sin20° in terms of p or q.

Therefore, we can't express sin130° only in terms of p and q.

Knowee AI · Accepted Answer

Sure, let's solve this step by step.

First, we need to understand the relationship between the angles given and the angle we want to find the sine of.

We know that sin(180° - θ) = sinθ and cos(180° - θ) = -cosθ.

So, sin130° = sin(180° - 50°) = sin50° = p.

Also, cos110° = cos(180° - 70°) = -cos70°. But cos70° = sin(90° - 70°) = sin20°.

However, we don't have a direct relationship to express sin20° in terms of p or q.

Therefore, we can't express sin130° only in terms of p and q.

Let 𝑝=sin50° and 𝑞=cos110°.Express sin130° in terms of 𝑝 and/or