The expression you provided is an application of the sine difference identity, which states that sin(A - B) = sin(A)cos(B) - cos(A)sin(B).

Here, A = 45° + θ and B = 15° + θ.

So, the expression simplifies to sin((45° + θ) - (15° + θ)) = sin(30°) = 0.5.

Question

The expression you provided is an application of the sine difference identity, which states that sin(A - B) = sin(A)cos(B) - cos(A)sin(B).

Here, A = 45° + θ and B = 15° + θ.

So, the expression simplifies to sin((45° + θ) - (15° + θ)) = sin(30°) = 0.5.

Knowee AI · Accepted Answer

The expression you provided is an application of the sine difference identity, which states that sin(A - B) = sin(A)cos(B) - cos(A)sin(B).

Here, A = 45° + θ and B = 15° + θ.

So, the expression simplifies to sin((45° + θ) - (15° + θ)) = sin(30°) = 0.5.

sin(45°+) cos(15°+ ) – cos(45°+ ) sin(15°+ )