100 g of CuI₂ are dissolved in 0.667 L of water. What is the mole fraction of CuI₂ in this solution?

Sure, here are the steps to calculate the mole fraction of CuI₂ in the solution:

1. First, we need to calculate the number of moles of CuI₂. The molar mass of CuI₂ (Copper(II) iodide) is approximately 413.4 g/mol. So, the number of moles of CuI₂ = mass / molar mass = 100 g / 413.4 g/mol = 0.242 moles.

2. Next, we need to calculate the number of moles of water. The molar mass of water (H₂O) is approximately 18.015 g/mol. The density of water is approximately 1 g/mL, so 0.667 L of water is 667 g. Therefore, the number of moles of water = mass / molar mass = 667 g / 18.015 g/mol = 37.03 moles.

3. The mole fraction of a component in a solution is the number of moles of that component divided by the total number of moles of all components. So, the mole fraction of CuI₂ = moles of CuI₂ / (moles of CuI₂ + moles of water) = 0.242 moles / (0.242 moles + 37.03 moles) = 0.0065.

So, the mole fraction of CuI₂ in the solution is 0.0065.