Let (an) and (bn) be bounded sequences, with bn̸ = 0 for all n. Consider thefour sequences(i) (an) (ii) (bn) (iii) (anbn) (iv) (an/bn)(a) Which of the sequences (i)–(iv) have convergent subsequences? Justifyyour answer. [6 marks](b) Suppose also that (an) and (bn) are monotonic. Which of the sequences(i)–(iv) must be convergent? Justify your answer.
Question
Let (an) and (bn) be bounded sequences, with bn̸ = 0 for all n. Consider thefour sequences(i) (an) (ii) (bn) (iii) (anbn) (iv) (an/bn)(a) Which of the sequences (i)–(iv) have convergent subsequences? Justifyyour answer. 6 marks Suppose also that (an) and (bn) are monotonic. Which of the sequences(i)–(iv) must be convergent? Justify your answer.
Solution
(a) According to the Bolzano-Weierstrass theorem, every bounded sequence has a convergent subsequence. Therefore, sequences (i) (an) and (ii) (bn) have convergent subsequences since they are both bounded.
For sequence (iii) (anbn), it is also bounded because it is a product of two bounded sequences. Therefore, it also has a convergent subsequence.
For sequence (iv) (an/bn), it is also bounded because it is a ratio of two bounded sequences where the denominator is not zero. Therefore, it also has a convergent subsequence.
(b) If the sequences (an) and (bn) are both monotonic and bounded, then according to the Monotone Convergence Theorem, they are convergent.
For sequence (iii) (anbn), it is not necessarily convergent because the product of two convergent sequences is not always convergent.
For sequence (iv) (an/bn), it is not necessarily convergent because the ratio of two convergent sequences is not always convergent.
Therefore, only sequences (i) (an) and (ii) (bn) must be convergent if they are monotonic and bounded.
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