Given an array arr of distinct elements of size n, the task is to rearrange the elements of the array in a zig-zag fashion so that the converted array should be in the below form: arr[0] < arr[1] > arr[2] < arr[3] > arr[4] < . . . . arr[n-2] < arr[n-1] > arr[n]. Note: Modify the given arr[] only, If your transformation is correct, the output will be 1 else the output will be 0
Question
Given an array arr of distinct elements of size n, the task is to rearrange the elements of the array in a zig-zag fashion so that the converted array should be in the below form: arr[0] < arr[1] > arr[2] < arr[3] > arr[4] < . . . . arr[n-2] < arr[n-1] > arr[n]. Note: Modify the given arr[] only, If your transformation is correct, the output will be 1 else the output will be 0
Solution
Sure, here is a step-by-step solution in Python:
- First, sort the array in ascending order. This can be done using the built-in sort() function in Python.
arr.sort()
- Now, we need to swap adjacent elements in the array to create the zig-zag pattern. We can do this by iterating over the array in steps of 2, starting from index 0, and swapping each pair of elements.
for i in range(0, n-1, 2):
arr[i], arr[i+1] = arr[i+1], arr[i]
- Finally, we need to check if the array is in the correct zig-zag pattern. We can do this by iterating over the array and checking if each element is less than the next element if its index is even, and greater than the next element if its index is odd. If we find any element that does not satisfy this condition, we return 0. If we reach the end of the array without finding any such element, we return 1.
for i in range(n-1):
if (i % 2 == 0 and arr[i] >= arr[i+1]) or (i % 2 == 1 and arr[i] <= arr[i+1]):
return 0
return 1
Here is the complete Python code:
def zigzag(arr):
n = len(arr)
arr.sort()
for i in range(0, n-1, 2):
arr[i], arr[i+1] = arr[i+1], arr[i]
for i in range(n-1):
if (i % 2 == 0 and arr[i] >= arr[i+1]) or (i % 2 == 1 and arr[i] <= arr[i+1]):
return 0
return 1
You can call this function with your array as the argument to rearrange it in zig-zag fashion and check if the transformation is correct.
Similar Questions
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