Sure, here is a step by step solution in Python:

1. First, you need to check if the length of the array is less than 3. If it is, there's no need to do anything because there's no (i+2)th element to swap with. You can simply return the array as it is.

```python
if len(arr)

Question

Sure, here is a step by step solution in Python:

1. First, you need to check if the length of the array is less than 3. If it is, there's no need to do anything because there's no (i+2)th element to swap with. You can simply return the array as it is.

```python
if len(arr) < 3:
    return arr
```

2. If the length of the array is 3 or more, you can use a for loop to iterate over the array. The loop should start from the 0th index and end at the (n-3)th index, where n is the length of the array. This is because the (i+2)th element for the (n-2)th and (n-1)th elements will be out of the array's range.

```python
for i in range(len(arr) - 2):
```

3. Inside the loop, you can use the Python's multiple assignment feature to swap the ith and (i+2)th elements.

```python
arr[i], arr[i+2] = arr[i+2], arr[i]
```

4. After the loop ends, return the modified array.

```python
return arr
```

Here's the complete function:

```python
def swap_elements(arr):
    if len(arr) < 3:
        return arr
    for i in range(len(arr) - 2):
        arr[i], arr[i+2] = arr[i+2], arr[i]
    return arr
```

You can call this function with an array as an argument to swap the elements as per the given condition.

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