Which element undergoes both oxidation and reduction?NaOH + Cl2 → NaClO + NaCl + H2O*ClNaOH

The element that undergoes both oxidation and reduction in the given reaction is Chlorine (Cl).

Here's the step-by-step explanation:

1. First, let's assign oxidation numbers to each element in the reaction:

   NaOH: Na(+1), O(-2), H(+1)

   Cl2: Cl(0) (since it's in its elemental form)

   NaClO: Na(+1), Cl(+1), O(-2)

   NaCl: Na(+1), Cl(-1)

   H2O: H(+1), O(-2)

2. Now, let's compare the oxidation numbers before and after the reaction:

   In Cl2, the oxidation number of Cl is 0. In NaClO, the oxidation number of Cl is +1, and in NaCl, it's -1.

3. From this, we can see that Cl has been both oxidized (from 0 to +1) and reduced (from 0 to -1) in the reaction.

So, Chlorine (Cl) is the element that undergoes both oxidation and reduction in this reaction.