Knowee
Questions
Features
Study Tools

400 kJ of energy is produced by a system at 100 K.  What is the change in entropy of the surroundings?Group of answer choices0 kJ/K. The entropy change is to the system, not the surroundings.+ 4 kJ/K- 4 kJ/KThe change in enthalpy of the surroundings must be known to do the calculation.

Question

400 kJ of energy is produced by a system at 100 K.  What is the change in entropy of the surroundings?Group of answer choices0 kJ/K. The entropy change is to the system, not the surroundings.+ 4 kJ/K- 4 kJ/KThe change in enthalpy of the surroundings must be known to do the calculation.

🧐 Not the exact question you are looking for?Go ask a question

Solution

The change in entropy of the surroundings can be calculated using the formula ΔS = Q/T, where ΔS is the change in entropy, Q is the heat transferred, and T is the temperature.

In this case, Q = 400 kJ (or 400,000 J to be in the base unit) and T = 100 K.

So, ΔS = Q/T = 400,000 J / 100 K = 4,000 J/K.

However, the answer choices are in kJ/K, so we need to convert J/K to kJ/K by dividing by 1000.

So, ΔS = 4,000 J/K ÷ 1000 = 4 kJ/K.

Therefore, the change in entropy of the surroundings is +4 kJ/K.

This problem has been solved

Similar Questions

Measurements show that the energy of a mixture of gaseous reactants decreases by 394.kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that −123.kJ of work is done on the mixture during the reaction.Calculate the change in enthalpy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. kJIs the reaction exothermic or endothermic? exothermicendothermic

What is the change in internal energy (in J) of a system that releases 675J of thermal energy to its surroundings and has ×4.90102cal of work done on it? Be sure your answer has the correct number of significant figures.

Calculate the change in entropy associated with freezing of 0.072 mol of C2 H 5 OHat 158.7 K given that the enthalpy of freezing is 4.60 kJ mol-1 .

An ideal gas receives 425 J of heat and expands by 1.50 L against an external pressure of 100.0 kPa.  What is the change in internal energy of the system? Use-full formula...!ΔW = p ΔV

Air is compress from 100 kPa and 50°C to 2000 kPa and 500°C. Assuming constant specific heats, determine the change in the specific entropy of air.Group of answer choices0.0478 kJ/kg.K1.767 kJ/kg.K-1.767 kJ/kg.K-0.0478 kJ/kg.K

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.